In ∆APB and ∆APC,
∠APB = ∠APC (Each 90º)
AB =AC (Given)
AP = AP (Common)
∠∆APB ≅ ∠∆APC (Using RHS congruence rule)
∠B = C (By using CPCT)
Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ∆ PQR (see Fig. 7.40). Show that:
(i) ∆ BM≅∆ PQN
(ii) ∆ ABC≅∆ PQR