The correct answer is 2
Minimum value of RL for which the diode is shorted is
\(\frac{R_L}{R_L}\)+100×10=8 ⇒RL=400 Ω
For maximum value of RL, current through diode is 10 mA.
So
\(i_R= i_{R_L} +I_{ZM}\)
\(\frac{2}{100}\)=\(\frac{8}{R_L}\)+10×10−3
10×10−3=\(\frac{8}{R_L}\)
RL = 800 Ω
So
\(\frac{R_{Lmax}}{R_{Lmin}}=\frac{800}{400}=2\)
So, ratio of maximum and minimum value of RL is 2
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is:
It is the rate of flow of electrons in a conductor. SI Unit - Ampere (A).
Electrons are negatively charged particles hence when they move a number of charges moves.
Note:- The ability of a particular substance to conduct electricity depends on the number of electrons that are able to move . Some of the materials allow current to flow better than others.
If a force acts on electrons to make them move in a particular direction, then up to some extent random motion of the electrons will be eliminated. An overall movement in one direction. The force which acts on the electrons to move them in a certain direction is known as electromotive force and its quantity is known as voltage and is measured in V.