Total turns $=72$ from $0$ to $3.6\,$V $\Rightarrow$ voltage per turn $=\dfrac{3.6}{72}=0.05\,$V.
Turn 35 potential $V_{35}=35\times0.05=1.75\,$V; turn 36 potential $V_{36}=36\times0.05=1.80\,$V.
With make-before-break, the wiper bridges turns 35 and 36, so the output equals the average:
\[
V_o=\frac{V_{35}+V_{36}}{2}=\frac{1.75+1.80}{2}=1.775\text{ V}\approx \boxed{1.78\text{ V}}.
\]