Question:

A wire of length L and radius r is rigidly clamped from one end and the other end is pulled by force F. It is found that the wire elongates by 5 cm. Another wire of the same material but 4L length and 4r radius is pulled by 4F force under identical conditions. What will be the final elongation of the wire?

Show Hint

- Elongation in a wire depends on force, length, cross-section, and material properties. - Thicker wires elongate less under the same force.
Updated On: Feb 10, 2025
  • 16 cm
  • 1/16 cm
  • 5 cm
  • 4 cm
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

- Using the elongation formula: \[ \Delta L = \frac{F L}{A E} \] - Since the second wire has 4 times the length and 16 times the area, the elongation is: \[ \Delta L' = \frac{F (4L)}{(16A)E} = \frac{1}{4} \times \Delta L = \frac{1}{4} \times 5 = 4 \text{ cm} \]
Was this answer helpful?
0
0

Top Questions on Strength of Materials

View More Questions