The velocity component vPS(t) along the line joining the source and the observer is given by:
vPS(t) = v(t) cosΟ
where Ο is the angle between the velocity vector and the line joining S and P.
From the geometry of the problem, the distance between the source and the observer is:
r(t) = β(x(t)Β² + LΒ²) = β(aΒ² sinΒ²(Οt) + LΒ²)
The angle Ο satisfies:
cosΟ = L / r(t)
Substituting v(t) = v0 cos(Οt) and cosΟ = L / r(t), we have:
vPS(t) = v0 cos(Οt) Γ (L / β(aΒ² sinΒ²(Οt) + LΒ²))
The component along the line of sight becomes:
vPS(t) = (1/2) Γ (a v0 / β(aΒ² sinΒ²(Οt) + LΒ²)) sin(2Οt)
Thus, statement (A) is correct.
The observed frequency is given by the Doppler effect, which depends on the relative velocity component vPS(t).
Hence, statement (B) is correct.
The correct statements are (A) and (B).
A particle is executing simple harmonic motion with a time period of 3 s. At a position where the displacement of the particle is 60% of its amplitude, the ratio of the kinetic and potential energies of the particle is:
The P-V diagram of an engine is shown in the figure below. The temperatures at points 1, 2, 3 and 4 are T1, T2, T3 and T4, respectively. 1β2 and 3β4 are adiabatic processes, and 2β3 and 4β1 are isochoric processes
Identify the correct statement(s).
[Ξ³ is the ratio of specific heats Cp (at constant P) and Cv (at constant V)]