
The velocity component vPS(t) along the line joining the source and the observer is given by:
vPS(t) = v(t) cosΟ
where Ο is the angle between the velocity vector and the line joining S and P.
From the geometry of the problem, the distance between the source and the observer is:
r(t) = β(x(t)Β² + LΒ²) = β(aΒ² sinΒ²(Οt) + LΒ²)
The angle Ο satisfies:
cosΟ = L / r(t)
Substituting v(t) = v0 cos(Οt) and cosΟ = L / r(t), we have:
vPS(t) = v0 cos(Οt) Γ (L / β(aΒ² sinΒ²(Οt) + LΒ²))
The component along the line of sight becomes:
vPS(t) = (1/2) Γ (a v0 / β(aΒ² sinΒ²(Οt) + LΒ²)) sin(2Οt)
Thus, statement (A) is correct.
The observed frequency is given by the Doppler effect, which depends on the relative velocity component vPS(t).
Hence, statement (B) is correct.
The correct statements are (A) and (B).
Using a variable frequency ac voltage source the maximum current measured in the given LCR circuit is 50 mA for V = 5 sin (100t) The values of L and R are shown in the figure. The capacitance of the capacitor (C) used is_______ Β΅F.

