Question:
A wheel of mass $ 10\,kg $ has a moment of inertia of $ 160\,kg-m^2 $ about its own axis, the radius of gyration will be
A wheel of mass $ 10\,kg $ has a moment of inertia of $ 160\,kg-m^2 $ about its own axis, the radius of gyration will be
Updated On: Jul 27, 2022
- 10 m
- 8 m
- 6 m
- 4 m
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The Correct Option is D
Solution and Explanation
Here : Mass of wheel $M=10\, kg$
Moment of inertia $=160\, kg\, m ^{2}$
(where $K$ is radius of gyration)
Using relation,
$I=M K^{2}$
$160=10 \times K^{2}$ or $K^{2}=16$
or $K=4\, m$
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