Question:

A wheel having moment of inertia $2\,kg-m^2$ about its vertical axis, rotates at the rate of $60$ rpm about this axis. The torque which can stop the wheel's rotation in one minute would be

Updated On: Jul 12, 2022
  • $\frac{2\pi}{15} N-m$
  • $\frac{\pi}{12} N-m$
  • $\frac{\pi}{15} N-m$
  • $\frac{\pi}{18} N-m$
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The Correct Option is C

Solution and Explanation

Given, $I=2 \,kg - m ^{2}, \omega_{0}=\frac{60}{60} \times 2 \pi\, rad / s$ $\omega=0, t=60\, s$ The torque required to stop the wheel's rotation is $\tau=I \alpha=I\left(\frac{\omega_{0}-\omega}{t}\right) $ $\therefore \tau=\frac{2 \times 2 \pi \times 60}{60 \times 60}$ $=\frac{\pi}{15} N - m$
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.