A wall is hit elastically and normally by ‘n’ balls per second. All the balls have the same mass ‘m’ and are moving with the same velocity ‘u’. the force exerted by the balls on the wall is
2mnu
\(\frac {1}{2}\)mnu2
mnu
2mnu2
The change in momentum of a ball is given by Δp = 2mu, where m is the mass of the ball and u is the velocity of the ball.
Since there are 'n' balls hitting the wall per second, the total change in momentum per second (rate of change of momentum) is given by:
Δptotal = n * Δp
Δptotal = n * 2mu
Δptotal = 2mnu
Therefore, the force exerted by the balls on the wall is equal to the rate of change of momentum:
F = \(\frac {Δp_{total}}{t}\)
Since the balls are hitting the wall per second, the time interval 't' is equal to 1 second.
F = Δptotal
Substituting the value of Δp_total:
F = 2mnu
Therefore, the correct answer is (A) 2mnu.
The collision theory states that a chemical reaction can only occur between particles when they collide (hit each other). The collision between reactant particles is necessary but not sufficient for a reaction to take place. The collisions also have to be effective. It is important to understand the exact nature of an effective collision since this determines whether particles react with each other and form new products.