Step 1: Understanding the system.
The system has a transfer function that is a rational function of \( s \). The poles of the system can be found by setting the denominator equal to zero:
\[
s(s-5) = 0 \quad \Rightarrow \quad s = 0, 5
\]
Since the pole at \( s = 0 \) is in the right half of the s-plane, the system is unstable.
Step 2: Analyzing the options.
- (A) Incorrect, the system is unstable due to the pole at \( s = 0 \).
- (B) Correct, the system is causal (since it has no future values depending on past inputs) but unstable due to the pole at \( s = 0 \).
- (C) Incorrect, the system is not non-causal, and it is unstable.
- (D) Incorrect, the system is not non-causal.
Step 3: Conclusion.
Thus, the correct answer is (B) Causal and unstable.