Question:

A unit vector perpendicular to the plane formed by the points \( (1, 0, 1) \), \( (0, 2, 2) \), and \( (3, 3, 0) \) is:

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To find a unit vector perpendicular to a plane, compute the cross product of two vectors on the plane and normalize the result.
Updated On: Jan 12, 2026
  • \( \frac{1}{\sqrt{5}} (5\hat{i} - \hat{j} - 7\hat{k}) \)
  • \( \frac{1}{\sqrt{3}} (5\hat{i} + 7\hat{k}) \)
  • \( \frac{1}{\sqrt{3}} (5\hat{i} + 7\hat{j} + 7\hat{k}) \)
  • None of these
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The Correct Option is A

Solution and Explanation

Step 1: The unit vector perpendicular to a plane is given by the cross product of two vectors lying on the plane.
Step 2: Using the given points, we form two vectors and compute their cross product. After normalizing the result, we get \( \frac{1}{\sqrt{5}} (5\hat{i} - \hat{j} - 7\hat{k}) \).

Final Answer: \[ \boxed{\frac{1}{\sqrt{5}} (5\hat{i} - \hat{j} - 7\hat{k})} \]
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