Question:

A uniform disc of radius R put over another uniform disc of radius 2R of same thickness and density, the peripheries of the two discs touch each other. The position of their centre of mass is

Updated On: Jul 6, 2022
  • at $\frac{R}{3}$ from the center of bigger disc towards the center of the smaller disc
  • at $\frac{R}{5}$ from the center of the bigger disc towards the center of the smaller disc
  • at $\frac{2R}{5}$ from the center of the bigger disc towards the center of the smaller disc
  • at $\frac{2R}{5}$ from the center of the smaller disc
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The Correct Option is B

Solution and Explanation

Distance of C.M. from centre of big disc $x = \frac{r^2 a}{R^2 +r^2}$ r- radius of small disc R- radius of big disc a- distance between the centres of discs
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Concepts Used:

Center of Mass

The center of mass of a body or system of a particle is defined as a point where the whole of the mass of the body or all the masses of a set of particles appeared to be concentrated.

The formula for the Centre of Mass:

Center of Gravity

The imaginary point through which on an object or a system, the force of Gravity is acted upon is known as the Centre of Gravity of that system. Usually, it is assumed while doing mechanical problems that the gravitational field is uniform which means that the Centre of Gravity and the Centre of Mass is at the same position.