Question

A triangular distributed load is applied on top of a beam as shown in the figure. The value of the maximum bending moment in kN-m is \(\underline{\hspace{1cm}}\). (round off to 2 decimal places) 

Hint:

For a triangular load, the maximum bending moment occurs at the center of the span.

Answer 1

Correct Answer: 1.2 - 1.35

The maximum bending moment \( M_{\text{max}} \) for a triangular load \( w = 5 \, \text{kN/m} \) over a span of \( L = 2 \, \text{m} \) is given by the formula:
\[ M_{\text{max}} = \frac{wL^2}{6} \] Substitute values:
\[ M_{\text{max}} = \frac{5 \times (2)^2}{6} = \frac{20}{6} = 3.33 \, \text{kN-m} \] Thus, the maximum bending moment is \( \boxed{3.33} \, \text{kN-m} \).