To convert the speed from \( \text{km/h} \) to \( \text{m/s} \), we use the following relation:
\[
1 \, \text{km/h} = \frac{1000 \, \text{m}}{3600 \, \text{s}} = \frac{5}{18} \, \text{m/s}.
\]
Convert \( 54 \, \text{km/h} \) to \( \text{m/s} \).
Now, to convert the speed of the train from kilometers per hour to meters per second, we multiply the speed in \( \text{km/h} \) by \( \frac{5}{18} \):
\[
\text{Speed in m/s} = 54 \, \text{km/h} \times \frac{5}{18}.
\]
\[
\text{Speed in m/s} = \frac{54 \times 5}{18} = 15 \, \text{m/s}.
\]
Thus, the speed of the train in \( \text{m/s} \) is \( 15 \, \text{m/s} \).