A tower $PQ$ stands on a horizontal ground with base $Q$ on the ground The point $R$ divides the tower in two parts such that $QR =15 \,m$ If from a point $A$ on the ground the angle of elevation of $R$ is $60^{\circ}$ and the part $PR$ of the tower subtends an angle of $15^{\circ}$ at $A$, then the height of the tower is :
- $5(2 \sqrt{3}+3) m$
- $5(\sqrt{3}+3) m$
- $10(\sqrt{3}+1) m$
- $10(2 \sqrt{3}+1) m$
The Correct Option is A
Solution and Explanation
From the given options the correct answer is option (A): $5(2 \sqrt{3}+3) m$
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Concepts Used:
Distance between Two Points
The distance between any two points is the length or distance of the line segment joining the points. There is only one line that is passing through two points. So, the distance between two points can be obtained by detecting the length of this line segment joining these two points. The distance between two points using the given coordinates can be obtained by applying the distance formula.
