Question:

A thin uniform rod of length L and mass M is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is ω. Its centre of mass rises to a maximum height of

  • \(\frac{1}{6}\frac{Lω}{g}\)
  • \(\frac{1}{2}\frac{L^2ω^2}{g}\)
  • \(\frac{1}{3}\frac{L^2ω^2}{g}\)
  • \(\frac{1}{6}\frac{L^2ω^2}{g}\)
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The Correct Option is D

Solution and Explanation

The correct option is (D): \(\frac{1}{6}\frac{L^2ω^2}{g}\)
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