Question:
A thin uniform circular ring is rolling down an inclined plane of induction 30$^\circ$ without slipping, its linear acceleration along the inclined plane will be
A thin uniform circular ring is rolling down an inclined plane of induction 30$^\circ$ without slipping, its linear acceleration along the inclined plane will be
Updated On: Jul 6, 2022
- $\frac {2}{3}g$
- $\frac {g}{3}$
- $\frac {g}{4}$
- $\frac {g}{2}$
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The Correct Option is C
Solution and Explanation
$a = \frac{g \, sin \theta}{1 + \frac{k^2}{R^2}} = \frac{g \, sin \, 30^\circ}{1 + 1} = \frac{g}{2} \times \frac{1}{2} = \frac{g}{4}$
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Concepts Used:
System of Particles and Rotational Motion
- The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
- The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
- The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.