Question:
A thin semicircular conducting ring of radius R is falling with its plane
vertical in a horizontal magnetic induction B. At the position MNQ
the speed of the ring is v and the potential difference developed across the ring is
A thin semicircular conducting ring of radius R is falling with its plane
vertical in a horizontal magnetic induction B. At the position MNQ
the speed of the ring is v and the potential difference developed across the ring is
Updated On: Jul 27, 2022
- zero
- Bv $ \pi \, R^2 \, / 2$ and M is at higher potential
- $\pi$ BRv and Q is at higher potential
- 2 RBv and Q is at higher potential
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The Correct Option is D
Solution and Explanation
Induced motional emf in MNQ is equivalent to the motional
emf in an imaginary wire MQ i.e.
$\hspace15mm$ $ e_{ MNQ} = e_{ MQ} = B v l = B v ( 2 R)$
$\hspace19mm$ [ t = MQ = 2 R ]
Therefore, potential difference developed across the ring is
2 RBv with Q at higher potential.
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter