Understanding the Concept
Work done by a gas in a thermodynamic process is given by the integral of pressure with respect to volume:
\[ W = \int P \, dV \]
In simpler terms, on a P-V diagram, the work done is represented by the area under the curve for the given process.
Analyzing Path bc
Looking at the P-V diagram, path bc is a vertical line. This means the volume remains constant during this process. Such a process is called an isochoric or isovolumetric process.
Since the volume doesn't change (dV = 0), the work done along this path is:
\[ W = \int P \, dV = 0 \]
Therefore, the work done by the gas along the path bc is 0.
For a given reaction \( R \rightarrow P \), \( t_{1/2} \) is related to \([A_0]\) as given in the table. Given: \( \log 2 = 0.30 \). Which of the following is true?
\([A]\) (mol/L) | \(t_{1/2}\) (min) |
---|---|
0.100 | 200 |
0.025 | 100 |
A. The order of the reaction is \( \frac{1}{2} \).
B. If \( [A_0] \) is 1 M, then \( t_{1/2} \) is \( 200/\sqrt{10} \) min.
C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M.
D. \( t_{1/2} \) is 800 min for \( [A_0] = 1.6 \) M.
The current passing through the battery in the given circuit, is:
Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is \(T_1\) and that at the right junction is \(T_2\). The ratio \(T_1 / T_2\) is