Understanding the Concept
Work done by a gas in a thermodynamic process is given by the integral of pressure with respect to volume:
\[ W = \int P \, dV \]
In simpler terms, on a P-V diagram, the work done is represented by the area under the curve for the given process.
Analyzing Path bc
Looking at the P-V diagram, path bc is a vertical line. This means the volume remains constant during this process. Such a process is called an isochoric or isovolumetric process.
Since the volume doesn't change (dV = 0), the work done along this path is:
\[ W = \int P \, dV = 0 \]
Therefore, the work done by the gas along the path bc is 0.
One mole of a monoatomic ideal gas starting from state A, goes through B and C to state D, as shown in the figure. Total change in entropy (in J K\(^{-1}\)) during this process is ...............
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