Let the amounts received by A, B, and C be represented by \( x \), \( y \), and \( z \), respectively. According to the problem:
- A gets Rs. 7 more than B: \( x = y + 7 \)
- B gets Rs. 8 more than C: \( y = z + 8 \)
We are given the total sum is Rs. 53:
\[
x + y + z = 53
\]
Substitute \( x = y + 7 \) and \( y = z + 8 \) into the equation:
\[
(y + 7) + y + z = 53
\]
Substitute \( y = z + 8 \) into this:
\[
(z + 8 + 7) + (z + 8) + z = 53
\]
Simplifying:
\[
3z + 15 = 53 \quad \Rightarrow \quad 3z = 38 \quad \Rightarrow \quad z = \frac{38}{3} \quad \Rightarrow \quad z = 12.67
\]
This gives the approximate values for \( z \), and we calculate the shares in the ratio accordingly.
Therefore, the correct answer is (A) 27 : 20 : 12.