We need the total amount after 2 years of compound interest.
- Step 1: Recall compound interest formul(a) Amount \( A = P \left(1 + \frac{r}{100}\right)^n \), where \( P \) is principal, \( r \) is rate, \( n \) is time.
- Step 2: Assign values. \( P = 10000 \), \( r = 5 \), \( n = 2 \).
\[
A = 10000 \left(1 + \frac{5}{100}\right)^2 = 10000 \times (1.05)^2
\]
- Step 3: Calculate \( (1.05)^2 \).
\[
1.05 \times 1.05 = 1.1025
\]
- Step 4: Compute amount.
\[
A = 10000 \times 1.1025 = 11025
\]
- Step 5: Alternative metho(d) Use binomial expansion for precision:
\[
(1.05)^2 = 1 + 2 \times 0.05 + (0.05)^2 = 1 + 0.1 + 0.0025 = 1.1025
\]
\[
A = 10000 \times 1.1025 = 11025
\]
- Step 6: Check options.
- (a) 11,000: Incorrect.
- (b) 11,025: Correct.
- (c) 11,050: Incorrect.
- (d) 11,100: Incorrect.
- Step 7: Verify. Simple interest check (for contrast): \( SI = 10000 \times 5% \times 2 = 1000 \), total = 11000, which is less than compound interest, confirming calculation.
Thus, the answer is b.