P - sum and r- rate of interest
Simple Interest \(=\frac{prt}{100}\)
Compound interest:
Amount \(=P(1+\frac{r}{100})^n\)
\(p(\frac{r}{100})^2=40\)
\(P(\frac{r}{100})^2\times\frac{(300+r)}{100}=61\)
On Solving, we get
P= 8000 (sum). So the correct option is (C)