To solve this problem, we need to determine which expressions can represent the displacement of a string stretched between two rigidly clamped points at \(x = 0\) and \(x = L\).
When a string is fixed at both ends, the displacement at these endpoints must be zero. Let's evaluate each given option under these boundary conditions:
- Option 1: \(x\cos \left(\frac{\pi x}{L}\right)\)
- At \(x = 0\), the displacement is \(0 \cdot \cos\left(0\right) = 0\).
- At \(x = L\), the displacement is \(L \cdot \cos\left(\pi\right) = -L\), which is not zero.
- Thus, this option does not satisfy the boundary condition at \(x = L\).
- Option 2: \(x\sin \left(\frac{\pi x}{L}\right)\)
- At \(x = 0\), the displacement is \(0 \cdot \sin(0) = 0\).
- At \(x = L\), the displacement is \(L \cdot \sin(\pi) = 0\).
- This option satisfies both boundary conditions, making it a valid expression for displacement.
- Option 3: \(x\left(\frac{x}{L} - 1\right)\)
- At \(x = 0\), the displacement is \(0 \cdot \left(0 - 1\right) = 0\).
- At \(x = L\), the displacement is \(L \cdot \left(1 - 1\right) = 0\).
- This option satisfies both boundary conditions as well.
- Option 4: \(x\left(\frac{x}{L} - 1\right)^2\)
- At \(x = 0\), the displacement is \(0 \cdot \left(-1\right)^2 = 0\).
- At \(x = L\), the displacement is \(L \cdot (0)^2 = 0\).
- This option also satisfies the boundary conditions at both ends.
From the analysis above, the expressions that can represent the displacement of the string are:
- \(x\sin \left(\frac{\pi x}{L}\right)\)
- \(x\left(\frac{x}{L} - 1\right)\)
- \(x\left(\frac{x}{L} - 1\right)^2\)
Hence, the correct answer is options 2, 3, and 4.