Question:
A stone is projected vertically up from the ground With velocity $40 ms^{-1}$ The interval of time between the two instants at which the stone is at a height of 60 m above the ground is $(g = 10 ms^{-2})$
A stone is projected vertically up from the ground With velocity $40 ms^{-1}$ The interval of time between the two instants at which the stone is at a height of 60 m above the ground is $(g = 10 ms^{-2})$
Updated On: Jul 6, 2022
- 4 s
- 6 s
- 8 s
- 12s
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The Correct Option is A
Solution and Explanation
hint : possible time intervals at which stone is at height h
$t = \frac{u - \sqrt{u^2 - 2gh}}{g}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.