Question:

A stick of length one meter is broken at two locations at distances of \( b_1 \) and \( b_2 \) from the origin (0), as shown in the figure. Note that \( 0<b_1<b_2<1 \). Which one of the following is NOT a necessary condition for forming a triangle using the three pieces? 
Note: All lengths are in meter. The figure shown is representative. 


 

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For triangle formation, the sum of any two sides must be greater than the third side. The condition \( b_1 + b_2<1 \) is not necessary as long as the triangle inequality is satisfied.
  • \( b_1<0.5 \)
  • \( b_2>0.5 \)
  • \( b_2<b_1 + 0.5 \)
  • \( b_1 + b_2<1 \)
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The Correct Option is D

Solution and Explanation

Step 1: Apply the triangle inequality theorem.
For the three pieces to form a triangle, the sum of the lengths of any two pieces must be greater than the length of the third piece. 
Step 2: Analyze the options. 
(A) \( b_1<0.5 \) is a necessary condition. If \( b_1 \) were greater than or equal to 0.5, the other pieces would be too small to form a triangle.
(B) \( b_2>0.5 \) is necessary because, if \( b_2 \leq 0.5 \), the sum of the two smaller pieces would not be enough to form a triangle.
(C) \( b_2<b_1 + 0.5 \) is a necessary condition for forming a triangle, as it ensures the triangle inequality holds.
(D) \( b_1 + b_2<1 \) is NOT a necessary condition for forming a triangle. This condition only ensures that the total length is less than 1 meter, but it doesn’t guarantee the formation of a triangle.

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