Ignoring power loss, power in primary = power in secondary. Power (P) = VI Primary voltage ($V_p$) = 220 V Secondary voltage ($V_s$) = 11000 V Power (P) = 88 W Secondary current ($I_s$) = ?
88 = 11000
$\implies i = \frac{88}{11 \times 10^3} = 8 \times 10^{-3} \text{ A}$
$\implies i = 8 \text{ mA}$
Assertion : In an ideal step-down transformer, the electrical energy is not lost.
Reason (R): In a step-down transformer, voltage decreases but the current increases.
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.