Question:

A square loop of copper wire is pulled through a region of uniform magnetic field as shown. Rank the pulling forces \(F_A\), \(F_B\), \(F_C\), and \(F_D\) that must be applied to keep the loop moving with constant speed (\(\vec{v}\)):
 square loop of copper wire is pulled through a region

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When considering the forces on a conducting loop in a magnetic field, the force is strongest where the field is most aligned and the length of the wire interacts with the magnetic flux.
Updated On: Apr 23, 2025
  • \(F_B = F_D, F_A = F_C\)
  • \(F_C>F_B = F_D>F_A\)
  • \(F_C>F_B>F_A\)
  • \(F_D>F_B>F_A = F_C\)
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The Correct Option is B

Solution and Explanation

When a conducting loop is moved through a magnetic field, the induced emf and the resulting current will generate forces on the segments of the wire. The forces are given by: \[ F = I L B \] Where \(I\) is the induced current, \(L\) is the length of the wire, and \(B\) is the magnetic field strength. - \(F_A\) acts on the side entering the magnetic field, with the least magnetic interaction. - \(F_B\) and \(F_D\) are the forces acting on the loop's sides where the magnetic field is strongest, as they are directly aligned with the field. - \(F_C\) is the force acting on the side of the wire where the magnetic field is cutting through the loop the most efficiently. Therefore, the ranking is: \[ F_C>F_B = F_D>F_A \]
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