Maximum mass that the scale can read, M = 50 kg
Maximum displacement of the spring = Length of the scale, l = 20 cm = 0.2 m
Time period, T = 0.6 s
Maximum force exerted on the spring, F = Mg
Where,
g = acceleration due to gravity = 9.8 m/s2
F = 50 × 9.8 = 490
∴Spring constant \(k=\frac{F}{l}\frac{490}{0.2}=2450\,Nm^{-1}\)
Mass m, is suspended from the balance
Time period, \(T=2\pi\sqrt\frac{m}{n}\)
\(∴ m=(\frac{T}{2\pi})×k=(\frac{0.6}{2×3.14})^2×2450=22.36 \,kg\)
∴Weight of the body = mg = 22.36 × 9.8 = 219.167 N
Hence, the weight of the body is about 219 N.
A test tube of mass 8 g and uniform cross-sectional area 12 cm2 is floating vertically in water. It contains 12 g of lead at the bottom. When the tube is slightly depressed and released, it performs vertical oscillations.
Find the time period of oscillation.
Give reasons for the following.
(i) King Tut’s body has been subjected to repeated scrutiny.
(ii) Howard Carter’s investigation was resented.
(iii) Carter had to chisel away the solidified resins to raise the king’s remains.
(iv) Tut’s body was buried along with gilded treasures.
(v) The boy king changed his name from Tutankhaten to Tutankhamun.