Question:

A sphere of diameter $0.2\, m$ and mass $2\, kg$ is rolling on an inclined plane with velocity $ v=0\, . 5\, m/s.$ The kinetic energy of the sphere is:

Updated On: Jul 12, 2022
  • 0.1 J
  • 0.3 J
  • 0.5 J
  • 0.42 J
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The kinetic energy of sphere while rolling on an inclined plane is given by $E_{ K }$ =Translational kinetic energy + Rotational kinetic energy $= \frac{1}{2} m v^{2}+\frac{1}{2} I \omega^{2}$ $E_{K}=\frac{1}{2} \times 2 \times(0.5)^{2}+\frac{1}{2} \times \frac{2}{3} \times 2 \times$ $(0.1)^{2} \times\left(\frac{0.5}{0.1}\right)^{2}$ $=0.25+0.17=0.42\, J$
Was this answer helpful?
0
0

Top Questions on System of Particles & Rotational Motion

View More Questions

Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.