A solution contains non volatile solute of molecular mass M2. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure
M2=(\(\frac{m_2}{\pi}\))VRT
M2=\((\frac{m_2}{V})\frac{RT}{\pi}\)
M2=\((\frac{m_2}{V})\pi RT\)
M2=\((\frac{m_2}{V})\frac{\pi}{RT}\)
The correct option is (B) : M2=\((\frac{m_2}{V})\frac{RT}{\pi}\)
For dilute solution, pV=nRT or \(\pi\)V=nRT or \(\pi\)V= \(\frac{m_2}{M_2}\) RT or M2 = \(\frac{m_2}{\pi V}\) RT where, \(\pi\) = osmotic pressure V =volume of solution n = number of moles of solute m2=mass of solute M2= molecular mass of solute
The freezing point depression constant (\( K_f \)) for water is \( 1.86 \, {°C·kg/mol} \). If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, calculate the freezing point depression.
Identify the major product C formed in the following reaction sequence:
Colligative Property of any substance is entirely dependent on the ratio of the number of solute particles to the total number of solvent particles but does not depend on the nature of particles. There are four colligative properties: vapor pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure.
We can notice the colligative properties of arrangements by going through the accompanying examples: