A solution contains non volatile solute of molecular mass M2. Which of the following can be used to calculate the molecular mass of solute in terms of osmotic pressure
M2=(\(\frac{m_2}{\pi}\))VRT
M2=\((\frac{m_2}{V})\frac{RT}{\pi}\)
M2=\((\frac{m_2}{V})\pi RT\)
M2=\((\frac{m_2}{V})\frac{\pi}{RT}\)
The correct option is (B) : M2=\((\frac{m_2}{V})\frac{RT}{\pi}\)
For dilute solution, pV=nRT or \(\pi\)V=nRT or \(\pi\)V= \(\frac{m_2}{M_2}\) RT or M2 = \(\frac{m_2}{\pi V}\) RT where, \(\pi\) = osmotic pressure V =volume of solution n = number of moles of solute m2=mass of solute M2= molecular mass of solute
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is:
Colligative Property of any substance is entirely dependent on the ratio of the number of solute particles to the total number of solvent particles but does not depend on the nature of particles. There are four colligative properties: vapor pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure.
We can notice the colligative properties of arrangements by going through the accompanying examples: