Question:
A solid metallic cube is melted to form five solid cubes whose volumes are in the ratio 1 : 1 : 8: 27: 27. The percentage by which the sum of the surface areas of these five cubes exceeds the surface area of the original cube is nearest to
A solid metallic cube is melted to form five solid cubes whose volumes are in the ratio 1 : 1 : 8: 27: 27. The percentage by which the sum of the surface areas of these five cubes exceeds the surface area of the original cube is nearest to
Updated On: Sep 26, 2024
- 10
- 50
- 60
- 20
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The Correct Option is B
Solution and Explanation
The volumes of the 5 smaller cubes and the original big one are in the ratio \(1:1:8:27:27:64. \)
Therefore, the sides are in the ratio \(1:1:2:3:3:4\), while the areas are in the ratio \(1:1:4:9:9:16. \)
The sum of the areas of the 5 smaller cubes is 24 parts, while that of the big cube is 16 parts.
The sum is 50% greater.
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