Question:

A solid cylinder of mass $ M $ and radius $ R $ rolls on a flat surface. Find its moment of inertia about the line of contact.

Updated On: Jun 6, 2024
  • $ \left(\frac{3}{2}\right)MR^{2} $
  • $ MR^2 $
  • $ 2\,MR^2 $
  • $ \left(\frac{2}{3}\right)MR^{2} $
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The Correct Option is A

Solution and Explanation



Moment of inertia of solid cylinder about $O$,
$I_{CM}=\frac{1}{2}MR^{2}$
Moment of inertia about point of contact $P$,
$I_{p}=I_{CM}+MR^{2}$ (using parallel axes theorem)
$=\frac{1}{2}MR^{2}+MR^{2}$
$=\frac{3}{2}MR^{2}$
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.