In this problem, we are dealing with the concept of flotation stability. The stability of a floating body depends on the relationship between the center of gravity (\( G \)), the center of buoyancy (\( B \)), and the metacentre (\( M \)). Let’s break down the important concepts:
1. Metacentre (\( M \)):
The metacentre is a point where the buoyant force (the upward force exerted by the fluid on the body) acts when the body is slightly tilted. The metacentre is the point of intersection of the vertical line through the center of buoyancy \( B \) when the body is tilted, with the axis of symmetry of the body in its equilibrium position.
2. Centre of Gravity (\( G \)):
The center of gravity is the point where the total weight of the body can be considered to act. It is the point where the force of gravity is effectively concentrated.
3. Centre of Buoyancy (\( B \)):
The center of buoyancy is the point where the buoyant force (or upward force) acts. This point is the centroid of the displaced fluid volume. It depends on the shape and size of the object submerged in the fluid.
Condition for Stability:
- For the body to be stable, the metacentre \( M \) must lie above the center of gravity \( G \). This condition ensures that when the body is tilted slightly, the buoyant force will create a restoring moment to return the body to its original position.
- The metacentric height \( MG \) is the distance between the metacentre \( M \) and the center of gravity \( G \). A higher metacentric height results in greater stability.
- Restoring Moment: When the body is tilted, the buoyant force must create a moment (a rotational force) that acts to restore the body to its upright position. This happens when the metacentre \( M \) lies above the center of gravity \( G \).
Conclusion:
For a floating body to return to its equilibrium position after being tilted, the metacentre \( M \) must be above the center of gravity \( G \), and the restoring moment must oppose the tilting force. Therefore, the center of gravity \( G \) should lie below the metacentre \( M \).
Thus, the correct option is:
\[ \boxed{(A) \, MG \, \text{is the metacentric height and} \, G \, \text{should lie below} \, M} \]
Consider two identical tanks with a bottom hole of diameter \( d \). One tank is filled with water and the other tank is filled with engine oil. The height of the fluid column \( h \) is the same in both cases. The fluid exit velocity in the two tanks are \( V_1 \) and \( V_2 \). Neglecting all losses, which one of the following options is correct?

A pitot tube connected to a U-tube mercury manometer measures the speed of air flowing in the wind tunnel as shown in the figure below. The density of air is 1.23 kg m\(^{-3}\) while the density of water is 1000 kg m\(^{-3}\). For the manometer reading of \( h = 30 \) mm of mercury, the speed of air in the wind tunnel is _________ m s\(^{-1}\) (rounded off to 1 decimal place).

Consider a velocity field \( \vec{V} = 3z \hat{i} + 0 \hat{j} + Cx \hat{k} \), where \( C \) is a constant. If the flow is irrotational, the value of \( C \) is (rounded off to 1 decimal place).