A small mass attached to a string rotates on a frictionless table top as shown. If the tension in the string is increased by pulling the string causing the radius of the circular motion to decrease by a factor of $2$ , the kinetic energy of the mass will
$ K \cdot E =\underset{ RI }{2} $ $\because$ From angular momentum conservation about centre. $L \rightarrow$ constant $I = mr$ $K \cdot E \cdot=\underset{2(\operatorname{tar})}{2,2} r =$ $K . E .=4 K . E .$ K.E. is increased by a factor of $4 .$
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