Question:

A series LCR circuit resonates at 10 kHZ. If the capacitor is 0.01 $\mu$F, the inductance used is approximately

Updated On: Jul 29, 2024
  • 10 mH
  • 25 mH
  • 50 mH
  • 100 mH
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The Correct Option is B

Solution and Explanation

$f=\frac{1}{2\pi}\frac{1}{\sqrt{LC}}, 10^{4} =\frac{1}{2\pi}\times\frac{1}{\sqrt{L\times10^{-8}}}, L\approx\frac{1}{40}H, L\approx25 mH$
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Concepts Used:

LCR Circuit

An LCR circuit, also known as a resonant circuit, or an RLC circuit, is an electrical circuit consist of an inductor (L), capacitor (C) and resistor (R) connected in series or parallel.

Series LCR circuit

When a constant voltage source is connected across a resistor a current is induced in it. This current has a unique direction and flows from the negative to positive terminal. Magnitude of current remains constant.

Alternating current is the current if the direction of current through this resistor changes periodically. An AC generator or AC dynamo can be used as AC voltage source.