Question

A saturated oil reservoir has an average reservoir pressure of 3000 psia, tested for flowing bottom-hole pressure (BHP) of 2000 psia and production rate of 500 STB/day. The maximum reservoir deliverability based on Vogel's equation for two-phase flow is \(\underline{\hspace{2cm}}\) STB/day.

Hint:

Vogel's equation helps estimate the maximum flow rate in oil reservoirs with two-phase flow based on pressures and production rate.

Answer 1

Correct Answer: 960

Vogel's equation for two-phase flow is given by:
\[ Q = \frac{q_0}{(1 - 0.2 \cdot \frac{BHP}{p_{avg}})} \] Where:
- \( q_0 = 500 \, \text{STB/day} \) is the production rate,
- \( BHP = 2000 \, \text{psia} \) is the bottom-hole pressure,
- \( p_{avg} = 3000 \, \text{psia} \) is the average reservoir pressure. Substituting the values into the equation:
\[ Q = \frac{500}{(1 - 0.2 \cdot \frac{2000}{3000})} = \frac{500}{(1 - 0.2 \cdot 0.6667)} = \frac{500}{(1 - 0.1333)} = \frac{500}{0.8667} \approx 576.46 \, \text{STB/day} \] Thus, the maximum reservoir deliverability is approximately \( \boxed{576.46} \, \text{STB/day} \).