A satellite of mass ‘m’ is revolving around the earth of mass ‘M’ in an orbit of radius ‘r’. The angular momentum of the satellite about the centre of orbit will be
The angular momentum (L) of a satellite revolving around a central body can be calculated using the formula:
L = mvr
To find the linear velocity (v) of the satellite, we can use the gravitational force equation:
=
Rearranging the equation, we can find the value of v:
v =
Substituting this value of v back into the formula for angular momentum:
L =
L =
Therefore, the correct answer is (B) for the angular momentum of the satellite about the center of the orbit.
A small point of mass is placed at a distance from the center of a big uniform solid sphere of mass and radius . The gravitational force on due to is . A spherical part of radius is removed from the big sphere as shown in the figure, and the gravitational force on due to the remaining part of is found to be . The value of the ratio is:
Kepler’s laws of planetary motion are three laws describing the motion of planets around the sun.
All the planets revolve around the sun in elliptical orbits having the sun at one of the foci.
It states that the radius vector drawn from the sun to the planet sweeps out equal areas in equal intervals of time.
It states that the square of the time period of revolution of a planet is directly proportional to the cube of its semi-major axis.
T2 ∝ a3