Question:

A satellite moves in elliptical orbit about a planet. Its maximum and minimum velocities of satellites are $ 3\times 10^4 \, m/s $ and $ 1 \times 10^3 \, m/s $ respectively. What is the minimum distance of satellite from planet is maximum distance if $ 4 \times 10^4\, km $

Updated On: Jun 20, 2022
  • $ 4 \times 10^3\, km $
  • $ 3 \times 10^3\, km $
  • $ 4/3 \times 10^3 \,km $
  • $ 1 \times 10^3\,km $
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The Correct Option is C

Solution and Explanation

If no external torque acts on a system, then angular momentum of the system does not change.
ie, If $\tau=0$
$\Rightarrow \frac{d L}{d t} =0$
$\therefore L=$ constant
Hence,
$m v_{\max } r_{\min } =m v_{\min } r_{\max }$
$\Rightarrow r_{\min } =\frac{v_{\min } \times r_{\max }}{v_{\max }}$
$=\frac{1 \times 10^{3} \times 4 \times 10^{4}}{3 \times 10^{4}}$
$=\frac{4}{3} \times 10^{3}\, km$
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].