A sample of H2SO4 is labeled as 86% by weight by weight. What is the molarity of acid?
Whet volume of acid to be used to make 1 litre of 0.2M H2SO4?
Molarity = n/v
Where, n= moles of solute
v= liter of solution
Moles of the solute= wt. of H₂SO₄ in1 L of solution/ mol wt. of H₂SO₄
Wt. of H₂SO₄ = strength x density x 1000
= 86/100 x1.787x 1000
= 1536.82
The molecular weight of H₂SO₄ is 98
Substituting the values, molarity = 1536.82/98 = 15.68 M
b) The molarity equation = M1V1= M2V2
In the question, M1= 15.68
M2= 0.2
V2= 1000
Substituting these values, 15.58 x V1= 0.2 X 1000
V1 = 200/15.68
= 12.75 mL
According to the generally accepted definition of the ideal solution there are equal interaction forces acting between molecules belonging to the same or different species. (This is equivalent to the statement that the activity of the components equals the concentration.) Strictly speaking, this concept is valid in ecological systems (isotopic mixtures of an element, hydrocarbons mixtures, etc.). It is still usual to talk about ideal solutions as limiting cases in reality since very dilute solutions behave ideally with respect to the solvent. This law is further supported by the fact that Raoult’s law empirically found for describing the behaviour of the solvent in dilute solutions can be deduced thermodynamically via the assumption of ideal behaviour of the solvent.
Answer the following questions:
(a) Give one example of miscible liquid pair which shows negative deviation from Raoult’s law. What is the reason for such deviation?
(b) (i) State Raoult’s law for a solution containing volatile components.
OR
(ii) Raoult’s law is a special case of Henry’s law. Comment.
(c) Write two characteristics of an ideal solution.