Comprehension
A salesman enters the quantity sold and the price into the computer. Both the numbers are two-digit numbers. But, by mistake, both the numbers were entered with their digits interchanged. The total sales value remained the same, i.e. Rs. 1,148, but the inventory reduced by 54.
Question: 1
What is the actual price per piece?
What is the actual price per piece?
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Digit interchange problems can be solved by expressing in $10a + b$ form.
Updated On: Aug 6, 2025
- Rs. 82
- Rs. 41
- Rs. 6
- Rs. 28
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The Correct Option is B
Solution and Explanation
Let quantity = $10a + b$ and price = $10b + a$.
Sales value: $(10a + b)(10b + a) = 1148$.
Inventory reduced by 54 means: $(10a + b) - (10b + a) = 54/(10b + a)$.
Solving gives $a = 4$, $b = 1$. Price = $10b + a = 41$ Rs.
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Question: 2
What is the actual quantity sold?
What is the actual quantity sold?
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Once digits $a$ and $b$ are found, substitute back to get both price and quantity.
Updated On: Aug 6, 2025
- 28
- 14
- 82
- 41
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The Correct Option is C
Solution and Explanation
From Q124, $a = 4$, $b = 1$. Quantity = $10a + b = 82$.
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