\(\frac gL\)
\(\frac {2g} {L}\)
\(\tau = I \alpha \)
\(\Rightarrow mg \left( \frac{L}{2} \right) = \left( \frac{ml^2}{3} \right) \alpha\)
\(\Rightarrow \alpha = \frac{3g}{2L}\)
So, the correct option is (B): \(\frac{3g}{2L}\)
A string of length \( L \) is fixed at one end and carries a mass of \( M \) at the other end. The mass makes \( \frac{3}{\pi} \) rotations per second about the vertical axis passing through the end of the string as shown. The tension in the string is ________________ ML.
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is: