Since the \(4\) rows of wires are needed.
Therefore the total length of wires is equal to \(4 \) times the perimeter of rectangle.
\(\text{Perimeter of field} = 2 \times (length + breadth)\)
= \(2 \times (0.7 + 0.5)\)
= \(2 \times 1.2 = 2.4 \;km\)
= \(2.4 \times 1000\) \(m\)
= \(2400\) \(m\)
Thus, the length of wire = \(4 \times 2400\)
= \(9600\) \(m\)
= \(9.6\) \(km\)
Column I shows different positions in which one pole of a magnet is placed near that of the other. Column II indicates the resulting action between them for each situation. Fill in the blanks.
Column I | Column II |
N-______ | _________ |
N-________ | Attraction |
S-N | |
________-S | Repulsion |
Draw:
1) a leaf
2) a taproot and
3) a flower,
you have studied for Table 4.3