Since the \(4\) rows of wires are needed.
Therefore the total length of wires is equal to \(4 \) times the perimeter of rectangle.
\(\text{Perimeter of field} = 2 \times (length + breadth)\)
= \(2 \times (0.7 + 0.5)\)
= \(2 \times 1.2 = 2.4 \;km\)
= \(2.4 \times 1000\) \(m\)
= \(2400\) \(m\)
Thus, the length of wire = \(4 \times 2400\)
= \(9600\) \(m\)
= \(9.6\) \(km\)
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow