Question

A ray PQ incident on the refracting face BC is refracted in the prism BA as shown in the figure and emerges from the other refracting face AC as RS such that \( \angle AQ = \angle RS \). If the angle of prism \( A = 60^\circ \) and the refractive index of the material of prism is \( \sqrt{3} \), then the angle of deviation of the ray is:

• A. \( 60^\circ \)
• B. \( 45^\circ \)
• C. \( 30^\circ \)
• D. None of these

Hint:

The angle of deviation is affected by the refractive index and the angle of incidence in a prism.

Answer 1

The Correct Option is A

Step 1: The angle of deviation \( \delta \) is the angle between the incident ray and the refracted ray after passing through the prism.
Step 2: The angle of deviation can be calculated using the formula: \[ \delta = \text{Angle of incidence} + \text{Angle of refraction} - \text{Angle of the prism}. \] Given the refractive index \( \mu = \sqrt{3} \), the deviation for the given angle is calculated to be \( 60^\circ \).

Final Answer: \[ \boxed{60^\circ} \]