Step 1: Understanding the Concept:
This is a mixture problem focusing on percentages. The key insight is that the amount of solid material (pulp) remains constant when a grape dehydrates into a raisin; only the amount of water changes.
Step 2: Detailed Explanation:
First, let's determine the percentage of pulp in both grapes and raisins.
Natural Grape: Contains 90% water, so it contains \(100% - 90% = 10%\) pulp.
Raisin: Contains 25% water, so it contains \(100% - 25% = 75%\) pulp.
We want to produce 4 kg of raisins. Let's calculate the amount of pulp in these raisins.
\[ \text{Weight of pulp in raisins} = 75% \text{ of } 4 \text{ kg} = 0.75 \times 4 = 3 \text{ kg} \]
This 3 kg of pulp must have come from the original natural grapes, as the pulp does not change weight.
Now, we need to find the total weight of natural grapes that would contain 3 kg of pulp. We know that pulp makes up 10% of the weight of natural grapes.
Let \(W\) be the required weight of natural grapes.
\[ 10% \text{ of } W = 3 \text{ kg} \]
\[ 0.10 \times W = 3 \]
\[ W = \frac{3}{0.10} \]
\[ W = 30 \text{ kg} \]
Step 3: Final Answer:
To obtain the 3 kg of pulp needed for 4 kg of raisins, 30 kg of natural grapes are required.