Question:

A raisin is a dehydrated grape. A natural grape contains 90% of water(by weight), and raisins contain 25% of water(by weight). How much weight of natural grapes (in kg) is required to make 4kgs of raisin?

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In problems involving dehydration or concentration changes, identify the component that remains constant (the solute or solid part). Set up your equations based on the quantity of this constant component.
Updated On: Sep 30, 2025
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
This is a mixture problem focusing on percentages. The key insight is that the amount of solid material (pulp) remains constant when a grape dehydrates into a raisin; only the amount of water changes.
Step 2: Detailed Explanation:
First, let's determine the percentage of pulp in both grapes and raisins.

Natural Grape: Contains 90% water, so it contains \(100% - 90% = 10%\) pulp.
Raisin: Contains 25% water, so it contains \(100% - 25% = 75%\) pulp.
We want to produce 4 kg of raisins. Let's calculate the amount of pulp in these raisins. \[ \text{Weight of pulp in raisins} = 75% \text{ of } 4 \text{ kg} = 0.75 \times 4 = 3 \text{ kg} \] This 3 kg of pulp must have come from the original natural grapes, as the pulp does not change weight. Now, we need to find the total weight of natural grapes that would contain 3 kg of pulp. We know that pulp makes up 10% of the weight of natural grapes.
Let \(W\) be the required weight of natural grapes. \[ 10% \text{ of } W = 3 \text{ kg} \] \[ 0.10 \times W = 3 \] \[ W = \frac{3}{0.10} \] \[ W = 30 \text{ kg} \] Step 3: Final Answer:
To obtain the 3 kg of pulp needed for 4 kg of raisins, 30 kg of natural grapes are required.
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