Question:
A radio transmitter transmits at 830 kHz. At a certain distance from the transmitter magnetic field has amplitude $4.82 \times 10^{-11}T$. The electric field and the wavelength are respectively
A radio transmitter transmits at 830 kHz. At a certain distance from the transmitter magnetic field has amplitude $4.82 \times 10^{-11}T$. The electric field and the wavelength are respectively
Updated On: Jul 2, 2022
- 0.014N/C, 36m
- 0.14N/C,36m
- 0.14N/C, 360m
- 0.014N/C,360m
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The Correct Option is D
Solution and Explanation
Frequency of EM wave $\upsilon= 830\, KHz$
$= 830 \times 10^{3}\,Hz$.
Magnetic field, $B = 4.82 \times 10^{-11} T$
As we know, frequency, $\upsilon = \frac{c}{\lambda}$
or $\lambda = \frac{c}{v} = \frac{3\times10^{8}}{830\times10^{3}}$
$\lambda \simeq 360\,m$
And, $E = BC = 4.82 \times 10^{-11} \times 3 \times 10^{8}$
$= 0.014 N/C$
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