Step 1: Continuous compounding formula.
\[
A = Pe^{rt}
\]
With \(r = 0.10\), \(t = 1\):
\[
A_{\text{continuous}} = Pe^{0.1} \approx P(1.10517)
\]
Step 2: Monthly compounding.
\[
A_{\text{monthly}} = P\left(1 + \frac{0.10}{12}\right)^{12}
\]
\[
= P(1.10471)
\]
Step 3: Compare amounts.
\[
1.10517 > 1.10471
\]
Thus, continuously compounded amount is slightly higher than monthly compounding.
Step 4: Eliminate wrong options.
- (B) False — continuous compounding is highest.
- (C) False — 1.365 corresponds to 36.5% interest, unrelated to 10%.
- (D) False — 27.18% is unrelated and much larger.
Conclusion: Continuous compounding gives more than monthly compounding.

