Given:
Step 1: Understanding Electrostatic Induction
When a charged object (glass rod) is brought near a conductor (metal sphere), it induces charge separation. The negative charges in the metal sphere move towards the glass rod, while the positive charges move away.
Step 2: What Happens When the Glass Rod is Removed?
Since the metal sphere is not grounded and no charge transfer has occurred, the charge redistribution disappears after removing the glass rod. The net charge on the sphere remains zero.
Answer: The correct option is A (Zero).
When a positively charged glass rod is brought near an uncharged metal sphere, it causes the electrons in the metal sphere to move due to electrostatic induction. Since the glass rod is positively charged, it will attract the free electrons in the metal sphere, causing a slight negative charge to accumulate on the side of the sphere nearest to the rod, while the far side becomes slightly positively charged. However, because the metal sphere is mounted on an insulated stand and no charge is allowed to flow in or out, once the glass rod is removed, the sphere remains neutral.
Thus, the net charge on the metal sphere will be zero after the glass rod is removed, as no charge is transferred to or from the sphere.
\(\textbf{Correct Answer:}\) (A) Zero

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R
Assertion A: Work done in moving a test charge between two points inside a uniformly charged spherical shell is zero, no matter which path is chosen.
Reason R: Electrostatic potential inside a uniformly charged spherical shell is constant and is same as that on the surface of the shell.
In the light of the above statements, choose the correct answer from the options given below
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: 