Question:
A polymer melt being extruded through a spinneret hole of circular cross-section exhibits a die-swell ratio of 2.2. The extrusion velocity and volumetric flow rate during this extrusion process are 20 m/min and \(2.6 \times 10^{-8}\) m\(^3\)/s, respectively. The maximum diameter (mm) of the extruded melt after exit from the spinneret hole (rounded off to 2 decimal places) is:
A polymer melt being extruded through a spinneret hole of circular cross-section exhibits a die-swell ratio of 2.2. The extrusion velocity and volumetric flow rate during this extrusion process are 20 m/min and \(2.6 \times 10^{-8}\) m\(^3\)/s, respectively. The maximum diameter (mm) of the extruded melt after exit from the spinneret hole (rounded off to 2 decimal places) is:
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Die-swell is the expansion of the polymer melt diameter due to the elasticity of the material. It is often used to calculate the extrudate size after it leaves the die.
Updated On: Apr 28, 2025
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Solution and Explanation
1. Calculate spinneret hole diameter ($D_0$):
The maximum diameter of the extruded melt is 0.69 mm.
Q = A₀ × v
A₀ = Q / v = 2.6e-8 m³/s / 0.333 m/s
A₀ = 7.81e-8 m²
D₀ = √(4A₀ / π) = √(4 × 7.81e-8 m² / π)
D₀ = 3.15e-4 m = 0.315 mm
2. Calculate extruded diameter ($D$):D = B × D₀
D = 2.2 × 0.315 mm
D = 0.693 mm
Final Answer:The maximum diameter of the extruded melt is 0.69 mm.
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