Q = A₀ × v
A₀ = Q / v = 2.6e-8 m³/s / 0.333 m/s
A₀ = 7.81e-8 m²
D₀ = √(4A₀ / π) = √(4 × 7.81e-8 m² / π)
D₀ = 3.15e-4 m = 0.315 mm
2. Calculate extruded diameter ($D$):D = B × D₀
D = 2.2 × 0.315 mm
D = 0.693 mm
Final Answer:Match the following polymers with their applications: