Question:

A planet is observed by an astronomical refracting telescope having an objective of focal length 16 m and an eyepiece of focal length 2 cm

Updated On: Aug 15, 2022
  • the distance between the objective and the eyepiece is 16.02 m
  • the angular magnification of the planet is -800
  • the image of the planet is inverted
  • the objective is larger than the eyepiece
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The Correct Option is D

Solution and Explanation

Distance between objective and eyepiece $ \, \, \, L=f_o+f_e=(16+0.02)m=16.02$m Angular magnification $\hspace10mm M=-f_o/f_e=-16/0.02=-800$ Image is inverted and objective is larger than the eyepiece.
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Ray Optics and Optical Instruments

Optics, deals with the determination of behaviour and the properties of light, along with its interactions with the matter and also with the instruments that are used to detect it.

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