10m/s2
9.8m/s2
20m/s2
2.5m/s2
5m/s2
Given:
Step 1: Relate Escape Speed to Gravity
Escape speed is given by:
\[ v_e = \sqrt{\frac{2GM}{R}} \]
where \( G \) is the gravitational constant and \( M \) is the planet's mass.
Step 2: Express Surface Gravity
Acceleration due to gravity at the surface (\( g \)) is:
\[ g = \frac{GM}{R^2} \]
Step 3: Solve for \( g \) Using Escape Speed
Square the escape speed equation:
\[ v_e^2 = \frac{2GM}{R} \implies GM = \frac{v_e^2 R}{2} \]
Substitute \( GM \) into the gravity formula:
\[ g = \frac{v_e^2 R}{2 R^2} = \frac{v_e^2}{2R} \]
Plug in the given values:
\[ g = \frac{(10,000)^2}{2 \times 10^7} = \frac{10^8}{2 \times 10^7} = 5 \, \text{m/s}^2 \]
Conclusion:
The acceleration due to gravity at the planet's surface is 5 m/s\(^2\).
Answer: \(\boxed{E}\)
1. Recall the formula for escape speed:
The escape speed (ve) of a planet is given by:
\[v_e = \sqrt{\frac{2GM}{R}}\]
where:
2. Relate escape speed to acceleration due to gravity:
The acceleration due to gravity (g) at the surface of a planet is given by:
\[g = \frac{GM}{R^2}\]
3. Combine the equations and solve for g:
From the escape speed equation, we can write:
\[v_e^2 = \frac{2GM}{R}\]
Now, multiply both sides by R:
\[v_e^2 R = 2GM\]
Divide both sides by 2R²:
\[\frac{v_e^2}{2R} = \frac{GM}{R^2} = g\]
4. Plug in the given values:
We are given \(v_e = 10 \, km/s = 10^4 \, m/s\) and \(R = 10,000 \, km = 10^7 \, m\). Substituting these values into the equation for g:
\[g = \frac{(10^4 \, m/s)^2}{2 \times 10^7 \, m} = \frac{10^8 \, m^2/s^2}{2 \times 10^7 \, m} = 5 \, m/s^2\]
Net gravitational force at the center of a square is found to be \( F_1 \) when four particles having masses \( M, 2M, 3M \) and \( 4M \) are placed at the four corners of the square as shown in figure, and it is \( F_2 \) when the positions of \( 3M \) and \( 4M \) are interchanged. The ratio \( \dfrac{F_1}{F_2} = \dfrac{\alpha}{\sqrt{5}} \). The value of \( \alpha \) is 

Escape speed is the minimum speed, which is required by the object to escape from the gravitational influence of a plannet. Escape speed for Earth’s surface is 11,186 m/sec.
The formula for escape speed is given below:
ve = (2GM / r)1/2
where ,
ve = Escape Velocity
G = Universal Gravitational Constant
M = Mass of the body to be escaped from
r = Distance from the centre of the mass