Question:

A person of height 1.6 m is walking away from a lamp post of height 4 m along a straight line on the horizontal ground. The lamp post and the person are always vertical. If the speed of the person is 60 cm/sec, then find the speed of tip point of its shadow with respect to the person in cm/sec.

Updated On: Aug 10, 2024
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Solution and Explanation

 a straight line on the horizontal ground
 
\(\frac{x_1+x_2}{x_2}=\frac{4}{1.6}=\frac{5}{2}\Rightarrow\,x_2=\frac{2}{3}x_1\)
\(\frac{dx_2}{dt}=\frac{2}{3}\frac{dx_1}{dt}\, where \,\frac{dx_1}{dt}=60cm/sec.\)
\(\frac{dx_2}{dt}=(\frac{2}{3})(60)=40 cm/sec.\)
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